NEET | JEE | MHT-CET CHEMISTRY |
PERIODIC PROPERTIES
PERIODIC PROPERTIES IMP MCQs WITH SOLUTION
1. According to
modern periodic law, the
chemical properties of elements
are the periodic functions of theirs.
(A)
Density
(B) Atomic number
(B) Atomic number
(C)
Mass number
(D) Atomic mass
(D) Atomic mass
2. Downwards in a group, electropositive character of elements.
(A)
Increases
(B) Decreases
(B) Decreases
(C) Remains same
(D) None
(D) None
3. Which of
the following has the largest ionic
radius?
(A)
Be +2
(B) Mg +2
(C) Ca +2
(D) Sr +2
(B) Mg +2
(C) Ca +2
(D) Sr +2
4. The size of
species l, l+ and l- decreases in the order
(A)
l+ > l- > l
(B) l- > l > l+
(B) l- > l > l+
(C)
l- > l+
> l
(D) l > l+ > l-
(D) l > l+ > l-
5. Which one of the following
ions has the smallest radius ?
(A)
Cl-
(B) S2
(C) K+
(D) Ca2+
(B) S2
(C) K+
(D) Ca2+
6. Which one of the following
is the smallest in size?
(A)
N3-
(B) O2-
(C) F-
(D) Na+
(B) O2-
(C) F-
(D) Na+
7. The correct order
of second ionisation
potential of carbon, nitrogen,
oxygen and fluroine is
(A) C > N> O > F
(B) O > N> F > C
(B) O > N> F > C
(C)
O > F > N > C
(D) F >O > N > C
(D) F >O > N > C
8. The
electronegativity of the
following elements increases
in the order
(A)
C, N, Si, P
(B) N, Si ,C, P
(B) N, Si ,C, P
(C)
Si, P, C, N
(D) P, Si, N, C
(D) P, Si, N, C
9. The radii of F, F- ,
O and O2- are in the order of
(A)
O2- > F- > F > O
(B) F-> O2- > F > O
(B) F-> O2- > F > O
(C)
O2- > O
> F- > F
(D) O2- > F- > O > F
(D) O2- > F- > O > F
10. Element X belongs to the 4th period. It contains 18 and 1 electron
in the penultimate and the ultimate shell. Therefore X is
(A)
Normal element
(B) Transition element
(B) Transition element
(C) Inert gas
(D) Inner transition element
(D) Inner transition element
Answers with Explanation
1. This is because
fluorine has got a
relatively high electron
density because of its smaller volume and as a result of this it has got
lower E. A. than chlorine.
That’s why fluoride formation is comparatively difficult.
2. By giving the l.P .,Na
is converted to Na+. Now
Na+ has an additional amount of
energy equal to its
l.P and in order to go back to its original state - it will liberate
energy and this we call
as electron affinity.
3. The alkali metals have one electron in
excess of their octet while alkaline earth metals have 2 e ‘s excess of their octet. So after 1st l. P. the alkali metal attains the inert gas configuration while alkaline earth metals attain it after 2nd l. P.Now removal from a
noble gas core needs high l. P., so there
is a jump in the 2nd l. P. for
alkali and 3rd l.P. for alkaline earth metals.
4. While F- is formed
from F then electron is added
to an electronegative, neutral
atom and energy (E.
A.) is released by this process but even
though O- formation
from O is energy-releasing process, formation of O2 from O-
is highly energy consuming
. So combined effect is O2- formation
form O is endothermic.
5. As we
go down the period the electronegativity decreases
. But after Al, due to the
presence of
d electrons which have
minimum shielding effect, the nuclear charge increases and hence electronegativity also increases.
6. From Li to Be the
additional electron is added
in the L shell which is
quite closer to nucleus whose
the charge also increases by 1 unit. So greater force is
experienced by the electrons and size contracts. In going from Na
to Mg and K to Ca
the electrons are
added in M and N shell
respectively which are away
from nucleus. Bring screening effects
into account also.
7. EA = - 3.477 eV
8. Ionisation energy
= 11.835 eV, Electron affinity = 3.358 eV
9. Alkaline earth metals have stable ns2 sonfiguration and are reluctant to accept
electrons.Thus their
electron affinity values are eithre small positive or negative.
10. The energy released in the formation of
three bonds as BX3 is more than enough for promoting of 2s electron to 2p orbital giving 3 equivalent
hybrid orbitals lying in a plane at an angle of 120o
Objective Answer Sheet
1
|
2
|
3
|
4
|
5
|
6
|
7
|
8
|
9
|
10
|
B
|
A
|
D
|
B
|
D
|
D
|
B
|
C
|
A
|
B
|


No comments:
Post a Comment